Imagine representing the collection of yearly salaries found at a startup using a simple list, for example:
(define salaries (list 100000 100000 50000 75000 500000))
And now imagine computing everyone’s updated salary after a standard cost-of-living adjustment (COLA).
We might decompose this problem into the problem of computing one person’s updated salary.
Let’s take the first person whom makes 100000 (units deliberately unspecified) as an example.
The Social Security COLA for 2020 was %1.6, so we can calculate the updated salary using arithmetic:
(+ 100000 (* 100000 0.016))
And we can abstract this into a function that computes the updated salary when given a salary:
;;; (compute-cola-salary salary) -> number?
;;; salary : number?, non-negative
;;; Returns the given salary, updated for cost-of-living.
(define compute-cola-salary
(lambda (salary)
(+ salary (* salary 0.016))))
Good! We can now calculate the updated salary for any person. However, how do we do this for a collection of salaries, a collection represented as a list?
Note that the calculation of each salary is independent of the other salaries.
That is, someone’s adjusted salary only depends on their salary and not other salaries.
In this situation, we simply want to apply our solution for a single person, compute-cola-salary, to every element of the list.
We say that we want to lift the function compute-cola-salary from operating on a single salary to a list of salaries.
In Scheme, we realize the behavior of lifting a function to a list of values with the map function:
(define salaries (list 100000 100000 50000 75000 500000))
(define compute-cola-salary
(lambda (salary)
(+ salary (* salary 0.016))))
(map compute-cola-salary salaries)
salaries
Note that the map procedure does not affect the original list.
map proceduremap is a powerful procedure!
It allows to concisely describe how to transform the values of a list in terms of an operation over a single element of the list.
Let’s break down how you use map.
map itself is a function of two arguments as seen in our above example.
The first argument is a function that transforms a single element of the list. By “transform”, we mean the function:
In our above example, compute-cola-salary is a function that transforms an old salary into a new, adjusted salary.
The second argument is a list that contains the elements that we wish to transform.
Any transformation function over salaries can be passed in to our call to map, for example, the startup might have gone public so everyone gets their salary doubled:
(define salaries (list 100000 100000 50000 75000 500000))
(define double-salary
(lambda (salary)
(* salary 2)))
(map double-salary salaries)
The startup might have hit a downturn and needs to reduce their salaries:
(define salaries (list 100000 100000 50000 75000 500000))
(define downsize
(lambda (salary)
(/ salary 2)))
(map downsize salaries)
Or worse yet, the downturn might be so bad that the startup needs to do the right thing and let go of its higher-earning employees to stay under budget:
(define salaries (list 100000 100000 50000 75000 500000))
(define should-keep
(lambda (salary)
(< salary 75000)))
(map should-keep salaries)
Observe that we have transformed our list of salaries into a list of booleans indicating whether we should keep the employee with that salary.
apply procedureapply is a helpful standard library function when working with lists of arguments. apply takes two arguments:
As a simple example of apply, consider the simple (+) function which can take any number of arguments:
(+ 1 2 3 4 5)
While (+) takes any number of arguments, it cannot take a single list as an argument:
(+ (list 1 2 3 4 5))
To pass this list of numbers to (+), we can use the apply function:
(apply + (list 1 2 3 4 5))
As you’ve likely discovered already, it is important that we use the correct types when
we run our procedures. With both map and apply, we have to think a bit more deeply
about types.
What are the types of the inputs to map?
That’s a real question. Take a minute and think about it.
We mean it.
Hopefully, you said something like
maptakes two inputs. The first is a procedure. The second is a list of values.
But there’s more to it than that. There’s a relationship between the procedure and the list of values. In particular, the procedure much be applicable to each value in the list. Let’s consider two simple examples.
You may remember that square computes the square of a number and string-upcase converts
a string to upper case.
(square 5) (string-upcase "quiet")
If we’re using map, we should use square with lists of numbers and string-upcase with
lists of numbers.
(range 6) (map square (range 6)) (string-split "please be quiet not loud" " ") (map string-upcase (string-split "please be quiet not loud" " "))
But what happens if we don’t match types? Let’s see.
(map square (string-split "please be quite not loud" " ")) (map string-upcase (range 6))
You’ll note that we get errors. Are they the errors you expected? It might be nicer if Scamper more explicitly told us that the elements of the list were not the correct types for the procedure. But it’s done that in its own way.
What if we do something even stranger, such as writing something other than a procedure in the procedure position, or something other than a list in the list position? Let’s try.
(map 5 (list 1 2 3)) (map square 5)
It’s good to see that these error messages are clear. Let’s do our best to remember those so that when we see them, we know what’s gone wrong.
Next, let’s move on to apply. Like map, apply takes a procedure and a list
as parameters. While map applies the procedure element by element, apply
applies the procedure to the elements en masse, as it were.
(apply * (list 2 3 4)) (apply string-append (list "this" "and" "that"))
Once again, we should see what happens if we give incorrect types.
(apply * (list 2 3 4)) (apply string-append (list "this" "and" "that")) (apply * (list "this" "and" "that")) (apply * (list 2 3 "four")) (apply string-append (list 2 3 4)) (apply 2 (list 2 3 4)) (apply 2 3) (apply + 2 3 4)
We will need to practice reading error messages like those. But each is saying, in essence, “you got the types wrong”.
map and applyAs we’ve seen, it’s useful to be able to trace our Scheme code by hand to consider what Scheme is doing (or at least what we think it’s doing) and, therefore, why we get the results or errors that we do. And you already know many aspects of the mental model for doing so, particularly the rule that you evaluate arguments before applying a procedure and that you use substitution for user-defined procedures.
(map f (list v1 v2 ... vk)) is equivalent to evaluating (list (f v1) (f v2) ... (f vk)).(apply f (list v1 v2 ... vk)) is equivalent to evaluating (f v1 v2 ... vk)So let’s try an example.
(define dub
(lambda (x)
(* 2 x)))
; (apply + (map dub (range 3 8 2)))
; --> (apply + (map dub (list 3 5 7)))
; --> (apply + (list (dub 3) (dub 5) (dub 7)))
; --> (apply + (list 6 (dub 5) (dub 7)))
; --> (apply + (list 6 10 (dub 7)))
; --> (apply + (list 6 10 14))
; --> (+ 6 10 14)
; --> 30
Note that when we’re working with lists, it’s helpful to explicitly write (list ...), which
reminds us that we’re dealing with a list and not an expression to further evaluate.
While we’ll rarely write out all of these steps, it helps to keep them in mind as
we think about what map and apply are doing. And we will, on occasion, pull
out a piece of paper (or an electronic document) to think through part of the
steps of an evaluation.
Write a function decrement that takes an integer as input and returns an integer one less than the input.
Now use decrement and map to write an expression that decrements the contents of the following list three times:
(define example-list (list 10 20 30 40 50))